2x^2+16x=80,5

Solution for 2x^2+16x=80,5 equation:

2x^2+16x=80.5

We move all terms to the left:

2x^2+16x-(80.5)=0

We add all the numbers together, and all the variables

2x^2+16x-80.5=0

a = 2; b = 16; c = -80.5;
Δ = b2-4ac
Δ = 162-4·2·(-80.5)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-30}{2*2}=\frac{-46}{4}
=-11+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+30}{2*2}=\frac{14}{4}
=3+1/2
$